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Mathematical Help


Rob
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ok eg converting 327, the way i do it might be a bit wierd.....

327/2=163 163x2=326 remainder =1 ( the remainder gives me the binary)

163/2=81 81x2=162 R=1

81/2=40 40x2=80 R=1

40/2=20 20x2=40 R=0

20/2=10 10x2=20 R=0

10/2=5 5x2=10 R=0

5/2=2 2x2=4 R=1

who else knows how to do it this way? if so can u finish the conversion?

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I do it a bit different fella....

Basically, I set up a grid like this:

Now basically make each bit one starting from the left, if they add up to more than the number you're after you know to leave that number as a 0, so we end up with something like this (I didn't start at 512 as we already know that is too big)

256 128  64   32   16    8    4    2    1

1    0    0    0    0    0    0    0    0 = 256 - ok
1    1    0    0    0    0    0    0    0 = 384 - too much
1    0    1    0    0    0    0    0    0 = 320 - ok
1    0    1    1    0    0    0    0    0 = 352 - too much
1    0    1    0    1    0    0    0    0 = 336 - too much
1    0    1    0    0    1    0    0    0 = 328 - too much
1    0    1    0    0    0    1    0    0 = 324 - ok
1    0    1    0    0    0    1    1    0 = 326 - ok
1    0    1    0    0    0    1    1    1 = 327 - bingo :)

So the binary value you're after is 101000111 - is that ok?

Does that make sense?

My MSN is fecked pal

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You were nearly there - just keep going.

To convert numbers from decimal to binary requires successive division.

To manually convert from a decimal to a binary number, start with the decimal number and begin dividing by the binary number base (base "two"). For each step the division results in a remainder of 1, use '1' in that position of the binary number. When the division results in a remainder of 0 instead, use '0' in that position. Stop when the division results in a value of 0. The resulting binary numbers are ordered from right to left.

For example, the decimal number 327 converts to binary as follows:

327 / 2 = 163 remainder 1

163 / 2 = 81 remainder 1

81 / 2 = 40 remainder 1

40 / 2 = 20 remainder 0

20 / 2 = 10 remainder 0

10 / 2 = 5 remainder 0

5 / 2 = 2 remainder 1

2 / 2 = 1 remainder 0

1 / 2 = 0 remainder 1

Therefore the decimal number 327 equals the binary number 101000111.

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Aaah, makes sense now.

Mark D's "successive division" method isn't what I would've used, but looks like a good method. Just get a few practice runs in first to get used to it (checking your answers with Calc or similar) before the exam!

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:lol:

Bugger me after all that too :P

Least you know how to count in binary now, there's a house down here and they have the house number as binary, I thought it was quite clever but I'm just a geek :lol:

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